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Generally I have found that the stuff right before the printed error is USUALLY the real cause, so I look at this:
WHERE language_id = $this_language_id and I see that if $this_language_id is null, which I bet it is, it will throw an error. Always a good idea to do this: language_id = '$this_language_id' ... for one thing, many a hack was done with a quoteless ID. Look up SQL-injection for the gory details. Anyway, may I suggest putting this in your toolbox: $sql="some query"; $db=mysql_query($sql); $ref = mysql_fetch_row($db); if (mysql_error()){ print mysql_error()."<br>$sql<br>"; exit(); } Seeing the Actual SQL after an error can usually speed up debugging by thousands! |
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excellent excellent and excellent! Thaks so much! Often the way you look at something for so long it ends up being something so simple. Exactly what you said, put the $this_language_id in quotes and hey presto all working.
Thanks so much Andy |